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253243404341 is a prime number
BaseRepresentation
bin1110101111011001111…
…0111011000000110101
3220012122222010212102222
43223312132323000311
513122120302414331
6312201033012125
724203415264044
oct3536636730065
9805588125388
10253243404341
1198444332a04
12410b6854045
131ab5b016965
14c38549855b
1568c293cb7b
hex3af67bb035

253243404341 has 2 divisors, whose sum is σ = 253243404342. Its totient is φ = 253243404340.

The previous prime is 253243404329. The next prime is 253243404343. The reversal of 253243404341 is 143404342352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138759975025 + 114483429316 = 372505^2 + 338354^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-253243404341 is a prime.

Together with 253243404343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253243404343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126621702170 + 126621702171.

It is an arithmetic number, because the mean of its divisors is an integer number (126621702171).

Almost surely, 2253243404341 is an apocalyptic number.

It is an amenable number.

253243404341 is a deficient number, since it is larger than the sum of its proper divisors (1).

253243404341 is an equidigital number, since it uses as much as digits as its factorization.

253243404341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 35.

Adding to 253243404341 its reverse (143404342352), we get a palindrome (396647746693).

The spelling of 253243404341 in words is "two hundred fifty-three billion, two hundred forty-three million, four hundred four thousand, three hundred forty-one".