Base | Representation |
---|---|
bin | 1011100001001111011010… |
… | …11010010110111100101000 |
3 | 10022200122210012000212212220 |
4 | 11300213231122112330220 |
5 | 11310012204221120230 |
6 | 125513030435234040 |
7 | 5223063556664115 |
oct | 560475532267450 |
9 | 108618705025786 |
10 | 25331405254440 |
11 | 8086a9697232a |
12 | 2a11490448920 |
13 | 1119983739c9c |
14 | 638091a6d90c |
15 | 2ddddbe21d10 |
hex | 1709ed696f28 |
25331405254440 has 128 divisors (see below), whose sum is σ = 76246820190720. Its totient is φ = 6732600019200.
The previous prime is 25331405254409. The next prime is 25331405254469. The reversal of 25331405254440 is 4445250413352.
It is a super-2 number, since 2×253314052544402 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 25331405254392 and 25331405254401.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 133801527 + ... + 133990713.
It is an arithmetic number, because the mean of its divisors is an integer number (595678282740).
Almost surely, 225331405254440 is an apocalyptic number.
25331405254440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 25331405254440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (38123410095360).
25331405254440 is an abundant number, since it is smaller than the sum of its proper divisors (50915414936280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
25331405254440 is a wasteful number, since it uses less digits than its factorization.
25331405254440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192903 (or 192899 counting only the distinct ones).
The product of its (nonzero) digits is 1152000, while the sum is 42.
Adding to 25331405254440 its reverse (4445250413352), we get a palindrome (29776655667792).
The spelling of 25331405254440 in words is "twenty-five trillion, three hundred thirty-one billion, four hundred five million, two hundred fifty-four thousand, four hundred forty".
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