Base | Representation |
---|---|
bin | 100100110111111110111… |
… | …001110101011001010101 |
3 | 22222020201200012222201110 |
4 | 210313332321311121111 |
5 | 313004124122424000 |
6 | 5220035330045233 |
7 | 351035121153351 |
oct | 44677671653125 |
9 | 8866650188643 |
10 | 2534012311125 |
11 | 897739985019 |
12 | 34b137719819 |
13 | 154c580b9419 |
14 | 8a90ad58461 |
15 | 45daeae2850 |
hex | 24dfee75655 |
2534012311125 has 16 divisors (see below), whose sum is σ = 4216596486336. Its totient is φ = 1351473232400.
The previous prime is 2534012311091. The next prime is 2534012311139. The reversal of 2534012311125 is 5211132104352.
It is a happy number.
It is not a de Polignac number, because 2534012311125 - 211 = 2534012309077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2534012311092 and 2534012311101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3378682707 + ... + 3378683456.
It is an arithmetic number, because the mean of its divisors is an integer number (263537280396).
Almost surely, 22534012311125 is an apocalyptic number.
2534012311125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2534012311125 is a deficient number, since it is larger than the sum of its proper divisors (1682584175211).
2534012311125 is an equidigital number, since it uses as much as digits as its factorization.
2534012311125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6757366181 (or 6757366171 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 2534012311125 its reverse (5211132104352), we get a palindrome (7745144415477).
The spelling of 2534012311125 in words is "two trillion, five hundred thirty-four billion, twelve million, three hundred eleven thousand, one hundred twenty-five".
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