Base | Representation |
---|---|
bin | 111001100111100111110010… |
… | …100010011011010010001110 |
3 | 1020020020220012120201220020222 |
4 | 321213213302202123102032 |
5 | 231203343104220322342 |
6 | 2254543334512311342 |
7 | 104243241404145605 |
oct | 7147476242332216 |
9 | 1206226176656228 |
10 | 253411434542222 |
11 | 73821205416300 |
12 | 24508a00842552 |
13 | ab52798ac15a8 |
14 | 4681270b90a3c |
15 | 1e46c2db13ed2 |
hex | e679f289b48e |
253411434542222 has 48 divisors (see below), whose sum is σ = 423484058269440. Its totient is φ = 113633048963280.
The previous prime is 253411434542219. The next prime is 253411434542237. The reversal of 253411434542222 is 222245434114352.
It is a super-3 number, since 3×2534114345422223 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14285168 + ... + 26662499.
It is an arithmetic number, because the mean of its divisors is an integer number (8822584547280).
Almost surely, 2253411434542222 is an apocalyptic number.
253411434542222 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
253411434542222 is a deficient number, since it is larger than the sum of its proper divisors (170072623727218).
253411434542222 is a wasteful number, since it uses less digits than its factorization.
253411434542222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40948037 (or 40948026 counting only the distinct ones).
The product of its digits is 1843200, while the sum is 44.
Adding to 253411434542222 its reverse (222245434114352), we get a palindrome (475656868656574).
The spelling of 253411434542222 in words is "two hundred fifty-three trillion, four hundred eleven billion, four hundred thirty-four million, five hundred forty-two thousand, two hundred twenty-two".
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