Base | Representation |
---|---|
bin | 111001100111110000001001… |
… | …101000110010101011000101 |
3 | 1020020021202101020110002120110 |
4 | 321213300021220302223011 |
5 | 231204020000434141240 |
6 | 2254551421411023233 |
7 | 104244010024361454 |
oct | 7147601150625305 |
9 | 1206252336402513 |
10 | 253420412021445 |
11 | 73824aa1a25319 |
12 | 2450a6a729ab19 |
13 | ab535999b7c86 |
14 | 46818831c2b9b |
15 | 1e470a6d42c80 |
hex | e67c09a32ac5 |
253420412021445 has 16 divisors (see below), whose sum is σ = 429323992130880. Its totient is φ = 127207108779264.
The previous prime is 253420412021417. The next prime is 253420412021461. The reversal of 253420412021445 is 544120214024352.
It is not a de Polignac number, because 253420412021445 - 210 = 253420412020421 is a prime.
It is a super-2 number, since 2×2534204120214452 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 496902768415 + ... + 496902768924.
It is an arithmetic number, because the mean of its divisors is an integer number (26832749508180).
Almost surely, 2253420412021445 is an apocalyptic number.
It is an amenable number.
253420412021445 is a deficient number, since it is larger than the sum of its proper divisors (175903580109435).
253420412021445 is a wasteful number, since it uses less digits than its factorization.
253420412021445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 993805537364.
The product of its (nonzero) digits is 307200, while the sum is 39.
Adding to 253420412021445 its reverse (544120214024352), we get a palindrome (797540626045797).
The spelling of 253420412021445 in words is "two hundred fifty-three trillion, four hundred twenty billion, four hundred twelve million, twenty-one thousand, four hundred forty-five".
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