Base | Representation |
---|---|
bin | 100100111111110010110… |
… | …111101000101111111011 |
3 | 100000001101020210011022222 |
4 | 210333302313220233323 |
5 | 313123313441434120 |
6 | 5223543530434255 |
7 | 351453023231030 |
oct | 44776267505773 |
9 | 10001336704288 |
10 | 2542400343035 |
11 | 8a02537935a3 |
12 | 35089889298b |
13 | 155993b40507 |
14 | 8b0a4d8d387 |
15 | 462011da525 |
hex | 24ff2de8bfb |
2542400343035 has 64 divisors (see below), whose sum is σ = 3713795205120. Its totient is φ = 1631051458560.
The previous prime is 2542400343031. The next prime is 2542400343061. The reversal of 2542400343035 is 5303430042452.
It is a happy number.
It is not a de Polignac number, because 2542400343035 - 22 = 2542400343031 is a prime.
It is a super-2 number, since 2×25424003430352 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a junction number, because it is equal to n+sod(n) for n = 2542400342986 and 2542400343004.
It is not an unprimeable number, because it can be changed into a prime (2542400343031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 406976282 + ... + 406982528.
It is an arithmetic number, because the mean of its divisors is an integer number (58028050080).
Almost surely, 22542400343035 is an apocalyptic number.
2542400343035 is a deficient number, since it is larger than the sum of its proper divisors (1171394862085).
2542400343035 is a wasteful number, since it uses less digits than its factorization.
2542400343035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10236.
The product of its (nonzero) digits is 172800, while the sum is 35.
Adding to 2542400343035 its reverse (5303430042452), we get a palindrome (7845830385487).
The spelling of 2542400343035 in words is "two trillion, five hundred forty-two billion, four hundred million, three hundred forty-three thousand, thirty-five".
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