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254849053 is a prime number
BaseRepresentation
bin11110011000010…
…11000000011101
3122202112200011211
433030023000131
51010220132203
641142144421
76213116104
oct1714130035
9582480154
10254849053
11120945958
1271422111
1340a4c874
1425bbd03b
1517590c6d
hexf30b01d

254849053 has 2 divisors, whose sum is σ = 254849054. Its totient is φ = 254849052.

The previous prime is 254849051. The next prime is 254849107. The reversal of 254849053 is 350948452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 254817369 + 31684 = 15963^2 + 178^2 .

It is a cyclic number.

It is not a de Polignac number, because 254849053 - 21 = 254849051 is a prime.

Together with 254849051, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 254848997 and 254849015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254849051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127424526 + 127424527.

It is an arithmetic number, because the mean of its divisors is an integer number (127424527).

Almost surely, 2254849053 is an apocalyptic number.

It is an amenable number.

254849053 is a deficient number, since it is larger than the sum of its proper divisors (1).

254849053 is an equidigital number, since it uses as much as digits as its factorization.

254849053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 40.

The square root of 254849053 is about 15963.9923891237. The cubic root of 254849053 is about 634.0074211234.

The spelling of 254849053 in words is "two hundred fifty-four million, eight hundred forty-nine thousand, fifty-three".