Base | Representation |
---|---|
bin | 1001011111111110… |
… | …0001100010000011 |
3 | 20120201022000220012 |
4 | 2113333201202003 |
5 | 20210300341120 |
6 | 1101011335135 |
7 | 120122513264 |
oct | 22777414203 |
9 | 6521260805 |
10 | 2550012035 |
11 | 109946286a |
12 | 5b1bb14ab |
13 | 3183c017c |
14 | 1a294c96b |
15 | edd091c5 |
hex | 97fe1883 |
2550012035 has 4 divisors (see below), whose sum is σ = 3060014448. Its totient is φ = 2040009624.
The previous prime is 2550012029. The next prime is 2550012061. The reversal of 2550012035 is 5302100552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2550012035 - 210 = 2550011011 is a prime.
It is a super-2 number, since 2×25500120352 = 13005122757289682450, which contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2550012035.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255001199 + ... + 255001208.
It is an arithmetic number, because the mean of its divisors is an integer number (765003612).
Almost surely, 22550012035 is an apocalyptic number.
2550012035 is a deficient number, since it is larger than the sum of its proper divisors (510002413).
2550012035 is an equidigital number, since it uses as much as digits as its factorization.
2550012035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 510002412.
The product of its (nonzero) digits is 1500, while the sum is 23.
The square root of 2550012035 is about 50497.6438559266. The cubic root of 2550012035 is about 1366.1993573489.
Adding to 2550012035 its reverse (5302100552), we get a palindrome (7852112587).
The spelling of 2550012035 in words is "two billion, five hundred fifty million, twelve thousand, thirty-five".
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