Base | Representation |
---|---|
bin | 111001111110111011101111… |
… | …110101111111011000001011 |
3 | 1020102221001012011012210010221 |
4 | 321332323233311333120023 |
5 | 231411114432001444210 |
6 | 2302211313320050511 |
7 | 104500053040103515 |
oct | 7176735765773013 |
9 | 1212831164183127 |
10 | 255013412140555 |
11 | 74289642a70682 |
12 | 24727383903a37 |
13 | ac3a87a64a353 |
14 | 46d8a01d84bb5 |
15 | 1e7373db331da |
hex | e7eeefd7f60b |
255013412140555 has 64 divisors (see below), whose sum is σ = 328959315717120. Its totient is φ = 189313627700736.
The previous prime is 255013412140519. The next prime is 255013412140559. The reversal of 255013412140555 is 555041214310552.
It is a cyclic number.
It is not a de Polignac number, because 255013412140555 - 29 = 255013412140043 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is not an unprimeable number, because it can be changed into a prime (255013412140559) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1287138841 + ... + 1287336949.
It is an arithmetic number, because the mean of its divisors is an integer number (5139989308080).
Almost surely, 2255013412140555 is an apocalyptic number.
255013412140555 is a deficient number, since it is larger than the sum of its proper divisors (73945903576565).
255013412140555 is a wasteful number, since it uses less digits than its factorization.
255013412140555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 199940.
The product of its (nonzero) digits is 600000, while the sum is 43.
The spelling of 255013412140555 in words is "two hundred fifty-five trillion, thirteen billion, four hundred twelve million, one hundred forty thousand, five hundred fifty-five".
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