Base | Representation |
---|---|
bin | 100101001001110011010… |
… | …100001011001000000011 |
3 | 100001002010002012120220011 |
4 | 211021303110023020003 |
5 | 313312320140221430 |
6 | 5232522043125351 |
7 | 352313214325306 |
oct | 45116324131003 |
9 | 10032102176804 |
10 | 2553145242115 |
11 | 8a4867a24286 |
12 | 352997213857 |
13 | 1569b6c5a770 |
14 | 8b804016b3d |
15 | 4662e68922a |
hex | 2527350b203 |
2553145242115 has 8 divisors (see below), whose sum is σ = 3299449236048. Its totient is φ = 1885399563360.
The previous prime is 2553145242113. The next prime is 2553145242127. The reversal of 2553145242115 is 5112425413552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2553145242115 - 21 = 2553145242113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2553145242113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19639578721 + ... + 19639578850.
It is an arithmetic number, because the mean of its divisors is an integer number (412431154506).
Almost surely, 22553145242115 is an apocalyptic number.
2553145242115 is a deficient number, since it is larger than the sum of its proper divisors (746303993933).
2553145242115 is a wasteful number, since it uses less digits than its factorization.
2553145242115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39279157589.
The product of its digits is 240000, while the sum is 40.
The spelling of 2553145242115 in words is "two trillion, five hundred fifty-three billion, one hundred forty-five million, two hundred forty-two thousand, one hundred fifteen".
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