Base | Representation |
---|---|
bin | 100101001001111110100… |
… | …000111100101101111001 |
3 | 100001002121011202210210212 |
4 | 211021332200330231321 |
5 | 313313211240442340 |
6 | 5232552434320505 |
7 | 352320655410461 |
oct | 45117640745571 |
9 | 10032534683725 |
10 | 2553333140345 |
11 | 8a4953aa0a79 |
12 | 352a2a129135 |
13 | 156a16b68650 |
14 | 8b820d68ba1 |
15 | 46640e02a65 |
hex | 2527e83cb79 |
2553333140345 has 16 divisors (see below), whose sum is σ = 3473360063040. Its totient is φ = 1786299459264.
The previous prime is 2553333140299. The next prime is 2553333140357. The reversal of 2553333140345 is 5430413333552.
It is a cyclic number.
It is not a de Polignac number, because 2553333140345 - 214 = 2553333123961 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1033736879 + ... + 1033739348.
It is an arithmetic number, because the mean of its divisors is an integer number (217085003940).
Almost surely, 22553333140345 is an apocalyptic number.
It is an amenable number.
2553333140345 is a deficient number, since it is larger than the sum of its proper divisors (920026922695).
2553333140345 is a wasteful number, since it uses less digits than its factorization.
2553333140345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2067476264.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 2553333140345 its reverse (5430413333552), we get a palindrome (7983746473897).
The spelling of 2553333140345 in words is "two trillion, five hundred fifty-three billion, three hundred thirty-three million, one hundred forty thousand, three hundred forty-five".
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