Base | Representation |
---|---|
bin | 111010000011111001010110… |
… | …010110011010001010111000 |
3 | 1020111010122102120122000111202 |
4 | 322003321112112122022320 |
5 | 231432211340142100240 |
6 | 2303032112505113332 |
7 | 104533514633643032 |
oct | 7203712626321270 |
9 | 1214118376560452 |
10 | 255354434331320 |
11 | 74400231115a75 |
12 | 24781497488848 |
13 | ac63a87237ccc |
14 | 470b31333ac52 |
15 | 1e7c54c8e0315 |
hex | e83e5659a2b8 |
255354434331320 has 32 divisors (see below), whose sum is σ = 580470647122800. Its totient is φ = 101088765754368.
The previous prime is 255354434331299. The next prime is 255354434331361. The reversal of 255354434331320 is 23133434453552.
255354434331320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32906495390 + ... + 32906503149.
Almost surely, 2255354434331320 is an apocalyptic number.
255354434331320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
255354434331320 is an abundant number, since it is smaller than the sum of its proper divisors (325116212791480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
255354434331320 is a wasteful number, since it uses less digits than its factorization.
255354434331320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65812998647 (or 65812998643 counting only the distinct ones).
The product of its (nonzero) digits is 7776000, while the sum is 47.
Adding to 255354434331320 its reverse (23133434453552), we get a palindrome (278487868784872).
The spelling of 255354434331320 in words is "two hundred fifty-five trillion, three hundred fifty-four billion, four hundred thirty-four million, three hundred thirty-one thousand, three hundred twenty".
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