Base | Representation |
---|---|
bin | 110000111010… |
… | …0000010101011 |
3 | 1210020201000112 |
4 | 1201310002223 |
5 | 23031004011 |
6 | 2313324535 |
7 | 430642325 |
oct | 141640253 |
9 | 53221015 |
10 | 25641131 |
11 | 1352361a |
12 | 870674b |
13 | 5409c89 |
14 | 3596615 |
15 | 23b758b |
hex | 18740ab |
25641131 has 4 divisors (see below), whose sum is σ = 25657512. Its totient is φ = 25624752.
The previous prime is 25641103. The next prime is 25641157. The reversal of 25641131 is 13114652.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 25641131 - 214 = 25624747 is a prime.
It is a super-2 number, since 2×256411312 = 1314935197918322, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25641097 and 25641106.
It is not an unprimeable number, because it can be changed into a prime (25641181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5561 + ... + 9066.
It is an arithmetic number, because the mean of its divisors is an integer number (6414378).
Almost surely, 225641131 is an apocalyptic number.
25641131 is a deficient number, since it is larger than the sum of its proper divisors (16381).
25641131 is a wasteful number, since it uses less digits than its factorization.
25641131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16380.
The product of its digits is 720, while the sum is 23.
The square root of 25641131 is about 5063.7072387728. The cubic root of 25641131 is about 294.8802769950.
Adding to 25641131 its reverse (13114652), we get a palindrome (38755783).
The spelling of 25641131 in words is "twenty-five million, six hundred forty-one thousand, one hundred thirty-one".
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