Base | Representation |
---|---|
bin | 100101100110010011001… |
… | …010011110001111011101 |
3 | 100011000002120210212101021 |
4 | 211212103022132033131 |
5 | 314313002022402312 |
6 | 5254542240044141 |
7 | 354445410351103 |
oct | 45462312361735 |
9 | 10130076725337 |
10 | 2583744340957 |
11 | 90683a36011a |
12 | 3588b6903651 |
13 | 159852494200 |
14 | 8d0a7c51c73 |
15 | 47320ba3c07 |
hex | 2599329e3dd |
2583744340957 has 12 divisors (see below), whose sum is σ = 2797900199424. Its totient is φ = 2384894300880.
The previous prime is 2583744340949. The next prime is 2583744340973. The reversal of 2583744340957 is 7590434473852.
It is not a de Polignac number, because 2583744340957 - 23 = 2583744340949 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2583744340895 and 2583744340904.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2583744340157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3861732 + ... + 4481122.
It is an arithmetic number, because the mean of its divisors is an integer number (233158349952).
Almost surely, 22583744340957 is an apocalyptic number.
It is an amenable number.
2583744340957 is a deficient number, since it is larger than the sum of its proper divisors (214155858467).
2583744340957 is a wasteful number, since it uses less digits than its factorization.
2583744340957 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 644100 (or 644087 counting only the distinct ones).
The product of its (nonzero) digits is 101606400, while the sum is 61.
The spelling of 2583744340957 in words is "two trillion, five hundred eighty-three billion, seven hundred forty-four million, three hundred forty thousand, nine hundred fifty-seven".
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