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25937005649 is a prime number
BaseRepresentation
bin11000001001111101…
…110100110001010001
32110221121001101220212
4120021331310301101
5411104333140044
615525412013505
71605512624162
oct301175646121
973847041825
1025937005649
11aaaa844265
12503a301295
1325a46b8829
1413809b7769
15a1c0ada9e
hex609f74c51

25937005649 has 2 divisors, whose sum is σ = 25937005650. Its totient is φ = 25937005648.

The previous prime is 25937005643. The next prime is 25937005651. The reversal of 25937005649 is 94650073952.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25199340049 + 737665600 = 158743^2 + 27160^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25937005649 is a prime.

It is a super-2 number, since 2×259370056492 (a number of 22 digits) contains 22 as substring.

Together with 25937005651, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 25937005597 and 25937005606.

It is not a weakly prime, because it can be changed into another prime (25937005643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12968502824 + 12968502825.

It is an arithmetic number, because the mean of its divisors is an integer number (12968502825).

Almost surely, 225937005649 is an apocalyptic number.

It is an amenable number.

25937005649 is a deficient number, since it is larger than the sum of its proper divisors (1).

25937005649 is an equidigital number, since it uses as much as digits as its factorization.

25937005649 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2041200, while the sum is 50.

The spelling of 25937005649 in words is "twenty-five billion, nine hundred thirty-seven million, five thousand, six hundred forty-nine".