Base | Representation |
---|---|
bin | 1101101100000101011000… |
… | …11000110111101111000111 |
3 | 10221120201120201222201111012 |
4 | 12312002230120313233013 |
5 | 12421142420342330041 |
6 | 144004402314232435 |
7 | 6224541122566601 |
oct | 666025430675707 |
9 | 127521521881435 |
10 | 30102023011271 |
11 | 96562182604a2 |
12 | 3461b8272571b |
13 | 13a47bb0c1c83 |
14 | 760d34d76171 |
15 | 37305191e3eb |
hex | 1b60ac637bc7 |
30102023011271 has 2 divisors, whose sum is σ = 30102023011272. Its totient is φ = 30102023011270.
The previous prime is 30102023011213. The next prime is 30102023011273. The reversal of 30102023011271 is 17211032020103.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30102023011271 is a prime.
It is a super-2 number, since 2×301020230112712 (a number of 28 digits) contains 22 as substring.
Together with 30102023011273, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30102023011273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15051011505635 + 15051011505636.
It is an arithmetic number, because the mean of its divisors is an integer number (15051011505636).
Almost surely, 230102023011271 is an apocalyptic number.
30102023011271 is a deficient number, since it is larger than the sum of its proper divisors (1).
30102023011271 is an equidigital number, since it uses as much as digits as its factorization.
30102023011271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 30102023011271 its reverse (17211032020103), we get a palindrome (47313055031374).
The spelling of 30102023011271 in words is "thirty trillion, one hundred two billion, twenty-three million, eleven thousand, two hundred seventy-one".
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