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301130000303 = 1127375454573
BaseRepresentation
bin1000110000111001011…
…11110010011110101111
31001210021021012222202012
410120130233302132233
514413203240002203
6350200500551435
730520165525016
oct4303457623657
91053237188665
10301130000303
11106788042250
124a43b9b257b
132251cc84742
141080924da7d
157c769bdbd8
hex461cbf27af

301130000303 has 4 divisors (see below), whose sum is σ = 328505454888. Its totient is φ = 273754545720.

The previous prime is 301130000291. The next prime is 301130000329. The reversal of 301130000303 is 303000031103.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 301130000303 - 216 = 301129934767 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (301130000333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13687727276 + ... + 13687727297.

It is an arithmetic number, because the mean of its divisors is an integer number (82126363722).

Almost surely, 2301130000303 is an apocalyptic number.

301130000303 is a deficient number, since it is larger than the sum of its proper divisors (27375454585).

301130000303 is a wasteful number, since it uses less digits than its factorization.

301130000303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27375454584.

The product of its (nonzero) digits is 81, while the sum is 14.

Adding to 301130000303 its reverse (303000031103), we get a palindrome (604130031406).

The spelling of 301130000303 in words is "three hundred one billion, one hundred thirty million, three hundred three", and thus it is an aban number.

Divisors: 1 11 27375454573 301130000303