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30121153117 = 112738286647
BaseRepresentation
bin11100000011010111…
…000101001001011101
32212202012021010012121
4130003113011021131
5443142003344432
621500520502541
72114300401636
oct340327051135
985665233177
1030121153117
1111857673180
125a0761aa51
132ac0503b33
14165a58488d
15bb45ab197
hex7035c525d

30121153117 has 4 divisors (see below), whose sum is σ = 32859439776. Its totient is φ = 27382866460.

The previous prime is 30121153091. The next prime is 30121153123. The reversal of 30121153117 is 71135112103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30121153117 - 27 = 30121152989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30121153091 and 30121153100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30121153817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1369143313 + ... + 1369143334.

It is an arithmetic number, because the mean of its divisors is an integer number (8214859944).

Almost surely, 230121153117 is an apocalyptic number.

It is an amenable number.

30121153117 is a deficient number, since it is larger than the sum of its proper divisors (2738286659).

30121153117 is a wasteful number, since it uses less digits than its factorization.

30121153117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2738286658.

The product of its (nonzero) digits is 630, while the sum is 25.

The spelling of 30121153117 in words is "thirty billion, one hundred twenty-one million, one hundred fifty-three thousand, one hundred seventeen".

Divisors: 1 11 2738286647 30121153117