3013001220221 has 2 divisors, whose sum is σ = 3013001220222. Its totient is φ = 3013001220220.

The previous prime is 3013001220209. The next prime is 3013001220223. The reversal of 3013001220221 is 1220221003103.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1637977627225 + 1375023592996 = 1279835^2 + 1172614^2 .

It is a cyclic number.

It is not a de Polignac number, because 3013001220221 - 2¹⁰ = 3013001219197 is a prime.

Together with 3013001220223, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3013001220221.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3013001220223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506500610110 + 1506500610111.

It is an arithmetic number, because the mean of its divisors is an integer number (1506500610111).

Almost surely, 2^{3013001220221} is an apocalyptic number.

It is an amenable number.

3013001220221 is a deficient number, since it is larger than the sum of its proper divisors (1).

3013001220221 is an equidigital number, since it uses as much as digits as its factorization.

3013001220221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 3013001220221 its reverse (1220221003103), we get a palindrome (4233222223324).

The spelling of 3013001220221 in words is "three trillion, thirteen billion, one million, two hundred twenty thousand, two hundred twenty-one".