30140010011 has 2 divisors, whose sum is σ = 30140010012. Its totient is φ = 30140010010.

The previous prime is 30140009953. The next prime is 30140010013. The reversal of 30140010011 is 11001004103.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 30140010011 - 2²² = 30135815707 is a prime.

Together with 30140010013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 30140009974 and 30140010001.

It is not a weakly prime, because it can be changed into another prime (30140010013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15070005005 + 15070005006.

It is an arithmetic number, because the mean of its divisors is an integer number (15070005006).

Almost surely, 2^30140010011 is an apocalyptic number.

30140010011 is a deficient number, since it is larger than the sum of its proper divisors (1).

30140010011 is an equidigital number, since it uses as much as digits as its factorization.

30140010011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 30140010011 its reverse (11001004103), we get a palindrome (41141014114).

It can be divided in two parts, 30 and 140010011, that added together give a palindrome (140010041).

The spelling of 30140010011 in words is "thirty billion, one hundred forty million, ten thousand, eleven".