Base | Representation |
---|---|
bin | 100010101000101000101101… |
… | …0001101001011010001010001 |
3 | 1110221200110102000010211022221 |
4 | 1011101101122031023101101 |
5 | 304412410032203041340 |
6 | 2555535131425301041 |
7 | 121112250606132415 |
oct | 10521213215132121 |
9 | 1427613360124287 |
10 | 304652133643345 |
11 | 890872761a4544 |
12 | 2a20375b194781 |
13 | 100cb75a967a07 |
14 | 5533355c72d45 |
15 | 2534a7b4dc44a |
hex | 115145a34b451 |
304652133643345 has 32 divisors (see below), whose sum is σ = 385274188558080. Its totient is φ = 230805120902400.
The previous prime is 304652133643339. The next prime is 304652133643367. The reversal of 304652133643345 is 543346331256403.
It is not a de Polignac number, because 304652133643345 - 23 = 304652133643337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 304652133643292 and 304652133643301.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 229535967 + ... + 230859403.
It is an arithmetic number, because the mean of its divisors is an integer number (12039818392440).
Almost surely, 2304652133643345 is an apocalyptic number.
It is an amenable number.
304652133643345 is a deficient number, since it is larger than the sum of its proper divisors (80622054914735).
304652133643345 is a wasteful number, since it uses less digits than its factorization.
304652133643345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1343385.
The product of its (nonzero) digits is 27993600, while the sum is 52.
Adding to 304652133643345 its reverse (543346331256403), we get a palindrome (847998464899748).
The spelling of 304652133643345 in words is "three hundred four trillion, six hundred fifty-two billion, one hundred thirty-three million, six hundred forty-three thousand, three hundred forty-five".
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