Base | Representation |
---|---|
bin | 101100011010100000000… |
… | …000101000110111111111 |
3 | 101210210000212212201010122 |
4 | 230122200000220313333 |
5 | 400001210443132033 |
6 | 10254042013325155 |
7 | 433336110005501 |
oct | 54324000506777 |
9 | 11723025781118 |
10 | 3052111302143 |
11 | a77436297332 |
12 | 413629a967bb |
13 | 191a74b16c27 |
14 | a7a19bb5d71 |
15 | 545d4634a98 |
hex | 2c6a0028dff |
3052111302143 has 2 divisors, whose sum is σ = 3052111302144. Its totient is φ = 3052111302142.
The previous prime is 3052111302139. The next prime is 3052111302169. The reversal of 3052111302143 is 3412031112503.
3052111302143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (3052111302169) can be obtained adding 3052111302143 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3052111302143 - 22 = 3052111302139 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3052111302043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526055651071 + 1526055651072.
It is an arithmetic number, because the mean of its divisors is an integer number (1526055651072).
Almost surely, 23052111302143 is an apocalyptic number.
3052111302143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3052111302143 is an equidigital number, since it uses as much as digits as its factorization.
3052111302143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 3052111302143 its reverse (3412031112503), we get a palindrome (6464142414646).
The spelling of 3052111302143 in words is "three trillion, fifty-two billion, one hundred eleven million, three hundred two thousand, one hundred forty-three".
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