Base | Representation |
---|---|
bin | 101100011010101100000… |
… | …110101000100001000111 |
3 | 101210210120000122222212002 |
4 | 230122230012220201013 |
5 | 400002114413401020 |
6 | 10254114102215515 |
7 | 433344122423024 |
oct | 54325406504107 |
9 | 11723500588762 |
10 | 3052314200135 |
11 | a7752a879622 |
12 | 413685a2459b |
13 | 191aa7b77305 |
14 | a7a38b1054b |
15 | 545e7362975 |
hex | 2c6ac1a8847 |
3052314200135 has 8 divisors (see below), whose sum is σ = 3689127954960. Its totient is φ = 2424284083584.
The previous prime is 3052314200119. The next prime is 3052314200141. The reversal of 3052314200135 is 5310024132503.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3052314200135 - 24 = 3052314200119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3052314200098 and 3052314200107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2195908802 + ... + 2195910191.
It is an arithmetic number, because the mean of its divisors is an integer number (461140994370).
Almost surely, 23052314200135 is an apocalyptic number.
3052314200135 is a deficient number, since it is larger than the sum of its proper divisors (636813754825).
3052314200135 is a wasteful number, since it uses less digits than its factorization.
3052314200135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4391819137.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 3052314200135 its reverse (5310024132503), we get a palindrome (8362338332638).
The spelling of 3052314200135 in words is "three trillion, fifty-two billion, three hundred fourteen million, two hundred thousand, one hundred thirty-five".
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