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30524331035 = 511554987837
BaseRepresentation
bin11100011011011001…
…000101010000011011
32220210021220200100002
4130123121011100123
51000003212043120
622004522203215
72130264350522
oct343331052033
986707820302
1030524331035
1111a44209770
125aba65350b
132b55bb8a53
141697d354b9
15bd9b9b375
hex71b64541b

30524331035 has 8 divisors (see below), whose sum is σ = 39959124336. Its totient is φ = 22199513440.

The previous prime is 30524331029. The next prime is 30524331049. The reversal of 30524331035 is 53013342503.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 30524331035 - 26 = 30524330971 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30524330989 and 30524331007.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 277493864 + ... + 277493973.

It is an arithmetic number, because the mean of its divisors is an integer number (4994890542).

Almost surely, 230524331035 is an apocalyptic number.

30524331035 is a deficient number, since it is larger than the sum of its proper divisors (9434793301).

30524331035 is a wasteful number, since it uses less digits than its factorization.

30524331035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 554987853.

The product of its (nonzero) digits is 16200, while the sum is 29.

Adding to 30524331035 its reverse (53013342503), we get a palindrome (83537673538).

The spelling of 30524331035 in words is "thirty billion, five hundred twenty-four million, three hundred thirty-one thousand, thirty-five".

Divisors: 1 5 11 55 554987837 2774939185 6104866207 30524331035