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30534311335 = 5113117908687
BaseRepresentation
bin11100011011111111…
…001001110110100111
32220210222200201201211
4130123333021312213
51000013240430320
622005520132251
72130445235563
oct343377116647
986728621654
1030534311335
1111a49906050
125b01a67087
132b57ca1658
1416993b26a3
15bda9bd55a
hex71bfc9da7

30534311335 has 16 divisors (see below), whose sum is σ = 41261617152. Its totient is φ = 21490423200.

The previous prime is 30534311329. The next prime is 30534311351. The reversal of 30534311335 is 53311343503.

It is not a de Polignac number, because 30534311335 - 217 = 30534180263 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30534311297 and 30534311306.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8952639 + ... + 8956048.

It is an arithmetic number, because the mean of its divisors is an integer number (2578851072).

Almost surely, 230534311335 is an apocalyptic number.

30534311335 is a deficient number, since it is larger than the sum of its proper divisors (10727305817).

30534311335 is a wasteful number, since it uses less digits than its factorization.

30534311335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17908734.

The product of its (nonzero) digits is 24300, while the sum is 31.

Adding to 30534311335 its reverse (53311343503), we get a palindrome (83845654838).

The spelling of 30534311335 in words is "thirty billion, five hundred thirty-four million, three hundred eleven thousand, three hundred thirty-five".

Divisors: 1 5 11 31 55 155 341 1705 17908687 89543435 196995557 555169297 984977785 2775846485 6106862267 30534311335