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3053540433005 = 5610708086601
BaseRepresentation
bin101100011011110101001…
…100010101110001101101
3101210220201111001002010022
4230123311030111301231
5400012122322324010
610254435504451525
7433416402266666
oct54336514256155
911726644032108
103053540433005
11a77aa9a72517
12413968619ba5
13191c41c24baa
14a7b1390c36d
1554669d30d55
hex2c6f5315c6d

3053540433005 has 4 divisors (see below), whose sum is σ = 3664248519612. Its totient is φ = 2442832346400.

The previous prime is 3053540432977. The next prime is 3053540433019. The reversal of 3053540433005 is 5003340453503.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1933696049476 + 1119844383529 = 1390574^2 + 1058227^2 .

It is not a de Polignac number, because 3053540433005 - 216 = 3053540367469 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305354043296 + ... + 305354043305.

It is an arithmetic number, because the mean of its divisors is an integer number (916062129903).

Almost surely, 23053540433005 is an apocalyptic number.

It is an amenable number.

3053540433005 is a deficient number, since it is larger than the sum of its proper divisors (610708086607).

3053540433005 is an equidigital number, since it uses as much as digits as its factorization.

3053540433005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 610708086606.

The product of its (nonzero) digits is 162000, while the sum is 35.

Adding to 3053540433005 its reverse (5003340453503), we get a palindrome (8056880886508).

The spelling of 3053540433005 in words is "three trillion, fifty-three billion, five hundred forty million, four hundred thirty-three thousand, five".

Divisors: 1 5 610708086601 3053540433005