Base | Representation |
---|---|
bin | 101100011011110101001… |
… | …100010101110011111110 |
3 | 101210220201111001002022200 |
4 | 230123311030111303332 |
5 | 400012122322330100 |
6 | 10254435504452330 |
7 | 433416402300264 |
oct | 54336514256376 |
9 | 11726644032280 |
10 | 3053540433150 |
11 | a77aa9a72639 |
12 | 41396861a0a6 |
13 | 191c41c24c8c |
14 | a7b1390c434 |
15 | 54669d30e00 |
hex | 2c6f5315cfe |
3053540433150 has 36 divisors (see below), whose sum is σ = 8203845298272. Its totient is φ = 814277448720.
The previous prime is 3053540433149. The next prime is 3053540433157. The reversal of 3053540433150 is 513340453503.
3053540433150 is a `hidden beast` number, since 3 + 0 + 5 + 35 + 40 + 433 + 150 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3053540433157) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 3392822254 + ... + 3392823153.
Almost surely, 23053540433150 is an apocalyptic number.
3053540433150 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3053540433150 is an abundant number, since it is smaller than the sum of its proper divisors (5150304865122).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3053540433150 is a wasteful number, since it uses less digits than its factorization.
3053540433150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6785645425 (or 6785645417 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 36.
Adding to 3053540433150 its reverse (513340453503), we get a palindrome (3566880886653).
The spelling of 3053540433150 in words is "three trillion, fifty-three billion, five hundred forty million, four hundred thirty-three thousand, one hundred fifty".
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