31004000111 has 4 divisors (see below), whose sum is σ = 35433142992. Its totient is φ = 26574857232.

The previous prime is 31004000089. The next prime is 31004000123. The reversal of 31004000111 is 11100040013.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-31004000111 is a prime.

It is a super-2 number, since 2×31004000111² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31004000092 and 31004000101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31004000171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2214571430 + ... + 2214571443.

It is an arithmetic number, because the mean of its divisors is an integer number (8858285748).

Almost surely, 2^31004000111 is an apocalyptic number.

31004000111 is a deficient number, since it is larger than the sum of its proper divisors (4429142881).

31004000111 is an equidigital number, since it uses as much as digits as its factorization.

31004000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4429142880.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 31004000111 its reverse (11100040013), we get a palindrome (42104040124).

The spelling of 31004000111 in words is "thirty-one billion, four million, one hundred eleven", and thus it is an aban number.