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310213002005 = 562042600401
BaseRepresentation
bin1001000001110100010…
…00101100001100010101
31002122201021111021200122
410200322020230030111
520040304012031010
6354302045121325
731261240003364
oct4407210541425
91078637437618
10310213002005
1110a619174925
1250155859245
13233399a646a
141102b6ad7db
1581090e3855
hex483a22c315

310213002005 has 4 divisors (see below), whose sum is σ = 372255602412. Its totient is φ = 248170401600.

The previous prime is 310213001963. The next prime is 310213002007. The reversal of 310213002005 is 500200312013.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 176835388324 + 133377613681 = 420518^2 + 365209^2 .

It is not a de Polignac number, because 310213002005 - 218 = 310212739861 is a prime.

It is a super-2 number, since 2×3102130020052 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (310213002007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31021300196 + ... + 31021300205.

It is an arithmetic number, because the mean of its divisors is an integer number (93063900603).

Almost surely, 2310213002005 is an apocalyptic number.

It is an amenable number.

310213002005 is a deficient number, since it is larger than the sum of its proper divisors (62042600407).

310213002005 is an equidigital number, since it uses as much as digits as its factorization.

310213002005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62042600406.

The product of its (nonzero) digits is 180, while the sum is 17.

Adding to 310213002005 its reverse (500200312013), we get a palindrome (810413314018).

The spelling of 310213002005 in words is "three hundred ten billion, two hundred thirteen million, two thousand, five".

Divisors: 1 5 62042600401 310213002005