3110014100129 has 2 divisors, whose sum is σ = 3110014100130. Its totient is φ = 3110014100128.

The previous prime is 3110014100107. The next prime is 3110014100131. The reversal of 3110014100129 is 9210014100113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2396365920400 + 713648179729 = 1548020^2 + 844777^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3110014100129 is a prime.

It is a Sophie Germain prime.

Together with 3110014100131, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (3110014100329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555007050064 + 1555007050065.

It is an arithmetic number, because the mean of its divisors is an integer number (1555007050065).

Almost surely, 2^{3110014100129} is an apocalyptic number.

It is an amenable number.

3110014100129 is a deficient number, since it is larger than the sum of its proper divisors (1).

3110014100129 is an equidigital number, since it uses as much as digits as its factorization.

3110014100129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 3110014100129 in words is "three trillion, one hundred ten billion, fourteen million, one hundred thousand, one hundred twenty-nine".