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311011231120230 = 235172382936598741
BaseRepresentation
bin100011010110111001111000…
…1111100111011101101100110
31111210012101100102221021202110
41012231303301330323231212
5311231102000131321410
63021244330453421450
7122336551144626234
oct10655636174735546
91453171312837673
10311011231120230
1190109138a15283
122aa7008803a886
13104703055b5634
1456b3049841954
1525e51b100c720
hex11adcf1f3bb66

311011231120230 has 256 divisors, whose sum is σ = 826011746150400. Its totient is φ = 74544931676160.

The previous prime is 311011231120229. The next prime is 311011231120283. The reversal of 311011231120230 is 32021132110113.

It is a super-2 number, since 2×3110112311202302 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311011231120197 and 311011231120206.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 35580733660 + ... + 35580742400.

It is an arithmetic number, because the mean of its divisors is an integer number (3226608383400).

Almost surely, 2311011231120230 is an apocalyptic number.

311011231120230 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 311011231120230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (413005873075200).

311011231120230 is an abundant number, since it is smaller than the sum of its proper divisors (515000515030170).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311011231120230 is a wasteful number, since it uses less digits than its factorization.

311011231120230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13279.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 311011231120230 its reverse (32021132110113), we get a palindrome (343032363230343).

The spelling of 311011231120230 in words is "three hundred eleven trillion, eleven billion, two hundred thirty-one million, one hundred twenty thousand, two hundred thirty".