311040433132 has 144 divisors (see below), whose sum is σ = 669226037760. Its totient is φ = 125557787520.

The previous prime is 311040433097. The next prime is 311040433177. The reversal of 311040433132 is 231334040113.

It is a junction number, because it is equal to n+sod(n) for n = 311040433097 and 311040433106.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17438803 + ... + 17456629.

It is an arithmetic number, because the mean of its divisors is an integer number (4647403040).

Almost surely, 2^311040433132 is an apocalyptic number.

It is an amenable number.

311040433132 is an abundant number, since it is smaller than the sum of its proper divisors (358185604628).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311040433132 is a wasteful number, since it uses less digits than its factorization.

311040433132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17972 (or 17959 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 311040433132 its reverse (231334040113), we get a palindrome (542374473245).

The spelling of 311040433132 in words is "three hundred eleven billion, forty million, four hundred thirty-three thousand, one hundred thirty-two".