311103320093941 has 2 divisors, whose sum is σ = 311103320093942. Its totient is φ = 311103320093940.

The previous prime is 311103320093939. The next prime is 311103320093981. The reversal of 311103320093941 is 149390023301113.

It is an a-pointer prime, because the next prime (311103320093981) can be obtained adding 311103320093941 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 308983587929041 + 2119732164900 = 17577929^2 + 1455930^2 .

It is a cyclic number.

It is not a de Polignac number, because 311103320093941 - 2¹ = 311103320093939 is a prime.

It is a super-2 number, since 2×311103320093941² (a number of 30 digits) contains 22 as substring.

Together with 311103320093939, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311103320093894 and 311103320093903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311103320093981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155551660046970 + 155551660046971.

It is an arithmetic number, because the mean of its divisors is an integer number (155551660046971).

Almost surely, 2^{311103320093941} is an apocalyptic number.

It is an amenable number.

311103320093941 is a deficient number, since it is larger than the sum of its proper divisors (1).

311103320093941 is an equidigital number, since it uses as much as digits as its factorization.

311103320093941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52488, while the sum is 40.

The spelling of 311103320093941 in words is "three hundred eleven trillion, one hundred three billion, three hundred twenty million, ninety-three thousand, nine hundred forty-one".