Base | Representation |
---|---|
bin | 1110001001011100110001… |
… | …10100111010100010001000 |
3 | 11002011011221221000211210122 |
4 | 13010232120310322202020 |
5 | 13034210323101224000 |
6 | 150100111321002412 |
7 | 6360460611611612 |
oct | 704563064724210 |
9 | 132134857024718 |
10 | 31111012133000 |
11 | 9a05119317608 |
12 | 35a5633023408 |
13 | 14489a97cc547 |
14 | 797ad11a1db2 |
15 | 38e407414085 |
hex | 1c4b98d3a888 |
31111012133000 has 64 divisors (see below), whose sum is σ = 72814706967600. Its totient is φ = 12441851251200.
The previous prime is 31111012132943. The next prime is 31111012133021. The reversal of 31111012133000 is 33121011113.
It can be written as a sum of positive squares in 8 ways, for example, as 853949720836 + 30257062412164 = 924094^2 + 5500642^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 31111012133000.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1687436 + ... + 8066564.
Almost surely, 231111012133000 is an apocalyptic number.
It is an amenable number.
31111012133000 is an abundant number, since it is smaller than the sum of its proper divisors (41703694834600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31111012133000 is a wasteful number, since it uses less digits than its factorization.
31111012133000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6384027 (or 6384013 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 31111012133000 its reverse (33121011113), we get a palindrome (31144133144113).
The spelling of 31111012133000 in words is "thirty-one trillion, one hundred eleven billion, twelve million, one hundred thirty-three thousand".
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