Base | Representation |
---|---|
bin | 1110001001011100111100… |
… | …00101010010110110101010 |
3 | 11002011012012001221212000122 |
4 | 13010232132011102312222 |
5 | 13034211013140004002 |
6 | 150100124151003242 |
7 | 6360463032254303 |
oct | 704563605226652 |
9 | 132135161855018 |
10 | 31111100313002 |
11 | 9a05164075546 |
12 | 35a5658669522 |
13 | 14489c1b64c68 |
14 | 797adcb977aa |
15 | 38e4100316a2 |
hex | 1c4b9e152daa |
31111100313002 has 4 divisors (see below), whose sum is σ = 46666650469506. Its totient is φ = 15555550156500.
The previous prime is 31111100313001. The next prime is 31111100313011. The reversal of 31111100313002 is 20031300111113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 21550197243961 + 9560903069041 = 4642219^2 + 3092071^2 .
It is not an unprimeable number, because it can be changed into a prime (31111100313001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7777775078249 + ... + 7777775078252.
Almost surely, 231111100313002 is an apocalyptic number.
31111100313002 is a deficient number, since it is larger than the sum of its proper divisors (15555550156504).
31111100313002 is a wasteful number, since it uses less digits than its factorization.
31111100313002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15555550156503.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 31111100313002 its reverse (20031300111113), we get a palindrome (51142400424115).
The spelling of 31111100313002 in words is "thirty-one trillion, one hundred eleven billion, one hundred million, three hundred thirteen thousand, two".
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