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311121300209 is a prime number
BaseRepresentation
bin1001000011100000100…
…01100100101011110001
31002202001120121121120212
410201300101210223301
520044134023101314
6354532133113505
731322606263166
oct4416021445361
91082046547525
10311121300209
1110aa449547a5
1250369a88895
1323452c16c15
14110b618a06d
15815dc0de3e
hex4870464af1

311121300209 has 2 divisors, whose sum is σ = 311121300210. Its totient is φ = 311121300208.

The previous prime is 311121300143. The next prime is 311121300211. The reversal of 311121300209 is 902003121113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 277778540209 + 33342760000 = 527047^2 + 182600^2 .

It is an emirp because it is prime and its reverse (902003121113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311121300209 - 28 = 311121299953 is a prime.

Together with 311121300211, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (311121300239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155560650104 + 155560650105.

It is an arithmetic number, because the mean of its divisors is an integer number (155560650105).

Almost surely, 2311121300209 is an apocalyptic number.

It is an amenable number.

311121300209 is a deficient number, since it is larger than the sum of its proper divisors (1).

311121300209 is an equidigital number, since it uses as much as digits as its factorization.

311121300209 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 311121300209 in words is "three hundred eleven billion, one hundred twenty-one million, three hundred thousand, two hundred nine".