Base | Representation |
---|---|
bin | 1110001001100000101010… |
… | …11101101100111111001001 |
3 | 11002011101100122202001202000 |
4 | 13010300111131230333021 |
5 | 13034224113404401301 |
6 | 150101055015501213 |
7 | 6360563462442501 |
oct | 704602535547711 |
9 | 132141318661660 |
10 | 31113103200201 |
11 | 9a05aa1704320 |
12 | 35a5b17387809 |
13 | 1448c50ab0509 |
14 | 797c4cba4a01 |
15 | 38e4cacb4786 |
hex | 1c4c1576cfc9 |
31113103200201 has 48 divisors (see below), whose sum is σ = 53069609603520. Its totient is φ = 17863982637120.
The previous prime is 31113103200121. The next prime is 31113103200203. The reversal of 31113103200201 is 10200230131113.
31113103200201 is a `hidden beast` number, since 3 + 1 + 11 + 310 + 320 + 0 + 20 + 1 = 666.
It is not a de Polignac number, because 31113103200201 - 27 = 31113103200073 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (31113103200203) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 144986860 + ... + 145201293.
It is an arithmetic number, because the mean of its divisors is an integer number (1105616866740).
Almost surely, 231113103200201 is an apocalyptic number.
It is an amenable number.
31113103200201 is a deficient number, since it is larger than the sum of its proper divisors (21956506403319).
31113103200201 is a wasteful number, since it uses less digits than its factorization.
31113103200201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 290188211 (or 290188186 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 31113103200201 its reverse (10200230131113), we get a palindrome (41313333331314).
The spelling of 31113103200201 in words is "thirty-one trillion, one hundred thirteen billion, one hundred three million, two hundred thousand, two hundred one".
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