311131301413 has 2 divisors, whose sum is σ = 311131301414. Its totient is φ = 311131301412.

The previous prime is 311131301353. The next prime is 311131301473. The reversal of 311131301413 is 314103131113.

It is a balanced prime because it is at equal distance from previous prime (311131301353) and next prime (311131301473).

It can be written as a sum of positive squares in only one way, i.e., 288877225729 + 22254075684 = 537473^2 + 149178^2 .

It is an emirp because it is prime and its reverse (314103131113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311131301413 - 2¹⁷ = 311131170341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311131301473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565650706 + 155565650707.

It is an arithmetic number, because the mean of its divisors is an integer number (155565650707).

Almost surely, 2^311131301413 is an apocalyptic number.

It is an amenable number.

311131301413 is a deficient number, since it is larger than the sum of its proper divisors (1).

311131301413 is an equidigital number, since it uses as much as digits as its factorization.

311131301413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 311131301413 its reverse (314103131113), we get a palindrome (625234432526).

The spelling of 311131301413 in words is "three hundred eleven billion, one hundred thirty-one million, three hundred one thousand, four hundred thirteen".