311131323133 has 4 divisors (see below), whose sum is σ = 313884697788. Its totient is φ = 308377948480.

The previous prime is 311131323101. The next prime is 311131323149. The reversal of 311131323133 is 331323131113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 331323131113 = 13 ⋅25486394701.

It can be written as a sum of positive squares in 2 ways, for example, as 24544548889 + 286586774244 = 156667^2 + 535338^2 .

It is a cyclic number.

It is not a de Polignac number, because 311131323133 - 2⁵ = 311131323101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311131323098 and 311131323107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311131329133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1376687158 + ... + 1376687383.

It is an arithmetic number, because the mean of its divisors is an integer number (78471174447).

Almost surely, 2^311131323133 is an apocalyptic number.

It is an amenable number.

311131323133 is a deficient number, since it is larger than the sum of its proper divisors (2753374655).

311131323133 is a wasteful number, since it uses less digits than its factorization.

311131323133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2753374654.

The product of its digits is 1458, while the sum is 25.

Adding to 311131323133 its reverse (331323131113), we get a palindrome (642454454246).

The spelling of 311131323133 in words is "three hundred eleven billion, one hundred thirty-one million, three hundred twenty-three thousand, one hundred thirty-three".