311132013000 has 128 divisors (see below), whose sum is σ = 973797102720. Its totient is φ = 82706553600.

The previous prime is 311132012999. The next prime is 311132013011. The reversal of 311132013000 is 310231113.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 787419 + ... + 1114581.

It is an arithmetic number, because the mean of its divisors is an integer number (7607789865).

Almost surely, 2^311132013000 is an apocalyptic number.

311132013000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311132013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (486898551360).

311132013000 is an abundant number, since it is smaller than the sum of its proper divisors (662665089720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311132013000 is a wasteful number, since it uses less digits than its factorization.

311132013000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327504 (or 327490 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 311132013000 its reverse (310231113), we get a palindrome (311442244113).

The spelling of 311132013000 in words is "three hundred eleven billion, one hundred thirty-two million, thirteen thousand".