Base | Representation |
---|---|
bin | 11100111111000001… |
… | …110001110111110111 |
3 | 2222022221220200020222 |
4 | 130333001301313313 |
5 | 1002214240431403 |
6 | 22144120444555 |
7 | 2151144232046 |
oct | 347701616767 |
9 | 88287820228 |
10 | 31122202103 |
11 | 12220743093 |
12 | 604691975b |
13 | 2c1ca1a605 |
14 | 17134c655d |
15 | c223e8338 |
hex | 73f071df7 |
31122202103 has 4 divisors (see below), whose sum is σ = 32760212760. Its totient is φ = 29484191448.
The previous prime is 31122202099. The next prime is 31122202117. The reversal of 31122202103 is 30120222113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30120222113 = 61 ⋅493774133.
It is a cyclic number.
It is not a de Polignac number, because 31122202103 - 22 = 31122202099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31122202123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 819005300 + ... + 819005337.
It is an arithmetic number, because the mean of its divisors is an integer number (8190053190).
Almost surely, 231122202103 is an apocalyptic number.
31122202103 is a deficient number, since it is larger than the sum of its proper divisors (1638010657).
31122202103 is a wasteful number, since it uses less digits than its factorization.
31122202103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1638010656.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 31122202103 its reverse (30120222113), we get a palindrome (61242424216).
The spelling of 31122202103 in words is "thirty-one billion, one hundred twenty-two million, two hundred two thousand, one hundred three".
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