Base | Representation |
---|---|
bin | 1110001001110001101011… |
… | …01001001010011101101110 |
3 | 11002012020220221002110100210 |
4 | 13010320311221022131232 |
5 | 13034401313122310110 |
6 | 150105204555203250 |
7 | 6361335642523041 |
oct | 704706551123556 |
9 | 132166827073323 |
10 | 31122233010030 |
11 | 9a099571a75a8 |
12 | 35a7844a46526 |
13 | 1449a77410856 |
14 | 79847752ac58 |
15 | 38e862583520 |
hex | 1c4e35a4a76e |
31122233010030 has 128 divisors (see below), whose sum is σ = 75679449753600. Its totient is φ = 8190212050944.
The previous prime is 31122233009981. The next prime is 31122233010101. The reversal of 31122233010030 is 3001033222113.
It is a junction number, because it is equal to n+sod(n) for n = 31122233009979 and 31122233010006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2127426756 + ... + 2127441384.
It is an arithmetic number, because the mean of its divisors is an integer number (591245701200).
Almost surely, 231122233010030 is an apocalyptic number.
31122233010030 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31122233010030 is an abundant number, since it is smaller than the sum of its proper divisors (44557216743570).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31122233010030 is a wasteful number, since it uses less digits than its factorization.
31122233010030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16778.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 31122233010030 its reverse (3001033222113), we get a palindrome (34123266232143).
The spelling of 31122233010030 in words is "thirty-one trillion, one hundred twenty-two billion, two hundred thirty-three million, ten thousand, thirty".
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