Base | Representation |
---|---|
bin | 1110001001110101111010… |
… | …00000101111000000000000 |
3 | 11002012110210012120110011020 |
4 | 13010322331000233000000 |
5 | 13034420441023110102 |
6 | 150110222204545440 |
7 | 6361446140551662 |
oct | 704727500570000 |
9 | 132173705513136 |
10 | 31124504113152 |
11 | 9a0a912180a2a |
12 | 35a8179552280 |
13 | 144a049aa8b58 |
14 | 798610dd6532 |
15 | 38e946b47bbc |
hex | 1c4ebd02f000 |
31124504113152 has 104 divisors (see below), whose sum is σ = 83794263406464. Its totient is φ = 10274107736064.
The previous prime is 31124504113069. The next prime is 31124504113231. The reversal of 31124504113152 is 25131140542113.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11030058 + ... + 13561385.
It is an arithmetic number, because the mean of its divisors is an integer number (805714071216).
Almost surely, 231124504113152 is an apocalyptic number.
31124504113152 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
31124504113152 is an abundant number, since it is smaller than the sum of its proper divisors (52669759293312).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31124504113152 is a wasteful number, since it uses less digits than its factorization.
31124504113152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24591573 (or 24591551 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 31124504113152 its reverse (25131140542113), we get a palindrome (56255644655265).
The spelling of 31124504113152 in words is "thirty-one trillion, one hundred twenty-four billion, five hundred four million, one hundred thirteen thousand, one hundred fifty-two".
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