Base | Representation |
---|---|
bin | 11100111111011111… |
… | …111111101101101101 |
3 | 2222100111211002211212 |
4 | 130333133333231231 |
5 | 1002223302414432 |
6 | 22145002324205 |
7 | 2151301452302 |
oct | 347737775555 |
9 | 88314732755 |
10 | 31130123117 |
11 | 12225163285 |
12 | 60494b9665 |
13 | 2c21561ac2 |
14 | 17145890a9 |
15 | c22e602b2 |
hex | 73f7ffb6d |
31130123117 has 2 divisors, whose sum is σ = 31130123118. Its totient is φ = 31130123116.
The previous prime is 31130123069. The next prime is 31130123119. The reversal of 31130123117 is 71132103113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23143841161 + 7986281956 = 152131^2 + 89366^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31130123117 is a prime.
Together with 31130123119, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 31130123092 and 31130123101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31130123119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565061558 + 15565061559.
It is an arithmetic number, because the mean of its divisors is an integer number (15565061559).
Almost surely, 231130123117 is an apocalyptic number.
It is an amenable number.
31130123117 is a deficient number, since it is larger than the sum of its proper divisors (1).
31130123117 is an equidigital number, since it uses as much as digits as its factorization.
31130123117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378, while the sum is 23.
The spelling of 31130123117 in words is "thirty-one billion, one hundred thirty million, one hundred twenty-three thousand, one hundred seventeen".
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