Base | Representation |
---|---|
bin | 1001000011110110000… |
… | …01000110000110010001 |
3 | 1002202112010202020101100 |
4 | 10201323001012012101 |
5 | 20100021142430001 |
6 | 355002052055013 |
7 | 31330225226400 |
oct | 4417301060621 |
9 | 1082463666340 |
10 | 311301530001 |
11 | 110027664040 |
12 | 503ba304469 |
13 | 2348136b577 |
14 | 110d20a3637 |
15 | 816e960586 |
hex | 487b046191 |
311301530001 has 72 divisors (see below), whose sum is σ = 574259160384. Its totient is φ = 160684655040.
The previous prime is 311301529999. The next prime is 311301530039. The reversal of 311301530001 is 100035103113.
311301530001 is a `hidden beast` number, since 3 + 1 + 130 + 1 + 530 + 0 + 0 + 1 = 666.
It is not a de Polignac number, because 311301530001 - 21 = 311301529999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311301530041) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 557236 + ... + 965978.
It is an arithmetic number, because the mean of its divisors is an integer number (7975821672).
Almost surely, 2311301530001 is an apocalyptic number.
It is an amenable number.
311301530001 is a deficient number, since it is larger than the sum of its proper divisors (262957630383).
311301530001 is a wasteful number, since it uses less digits than its factorization.
311301530001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 408931 (or 408921 counting only the distinct ones).
The product of its (nonzero) digits is 135, while the sum is 18.
Adding to 311301530001 its reverse (100035103113), we get a palindrome (411336633114).
The spelling of 311301530001 in words is "three hundred eleven billion, three hundred one million, five hundred thirty thousand, one".
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