31130404133 has 2 divisors, whose sum is σ = 31130404134. Its totient is φ = 31130404132.

The previous prime is 31130404121. The next prime is 31130404139. The reversal of 31130404133 is 33140403113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31040097124 + 90307009 = 176182^2 + 9503^2 .

It is an emirp because it is prime and its reverse (33140403113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31130404133 - 2⁴ = 31130404117 is a prime.

It is a super-2 number, since 2×31130404133² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31130404099 and 31130404108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31130404139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565202066 + 15565202067.

It is an arithmetic number, because the mean of its divisors is an integer number (15565202067).

Almost surely, 2^31130404133 is an apocalyptic number.

It is an amenable number.

31130404133 is a deficient number, since it is larger than the sum of its proper divisors (1).

31130404133 is an equidigital number, since it uses as much as digits as its factorization.

31130404133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 31130404133 its reverse (33140403113), we get a palindrome (64270807246).

The spelling of 31130404133 in words is "thirty-one billion, one hundred thirty million, four hundred four thousand, one hundred thirty-three".