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311311111343 = 317982053979
BaseRepresentation
bin1001000011110111001…
…01101001010010101111
31002202112210210000111212
410201323211221102233
520100031121030333
6355003033305035
731330402533341
oct4417345512257
91082483700455
10311311111343
11110032008701
125040156517b
13234833446bb
14110d3479291
158170704448
hex487b9694af

311311111343 has 4 divisors (see below), whose sum is σ = 312293165640. Its totient is φ = 310329057048.

The previous prime is 311311111277. The next prime is 311311111367. The reversal of 311311111343 is 343111113113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311311111343 is a prime.

It is a super-2 number, since 2×3113111113432 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311311111393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 491026673 + ... + 491027306.

It is an arithmetic number, because the mean of its divisors is an integer number (78073291410).

Almost surely, 2311311111343 is an apocalyptic number.

311311111343 is a deficient number, since it is larger than the sum of its proper divisors (982054297).

311311111343 is an equidigital number, since it uses as much as digits as its factorization.

311311111343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 982054296.

The product of its digits is 324, while the sum is 23.

Adding to 311311111343 its reverse (343111113113), we get a palindrome (654422224456).

The spelling of 311311111343 in words is "three hundred eleven billion, three hundred eleven million, one hundred eleven thousand, three hundred forty-three".

Divisors: 1 317 982053979 311311111343