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3113130055 = 5788946573
BaseRepresentation
bin1011100110001110…
…1001100001000111
322000221220101121011
42321203221201013
522333430130210
61232525103051
7140101111630
oct27143514107
98027811534
103113130055
11135830a762
1272a6b7a87
133a7c744b9
14217654887
1513348dd8a
hexb98e9847

3113130055 has 8 divisors (see below), whose sum is σ = 4269435552. Its totient is φ = 2134717728.

The previous prime is 3113130047. The next prime is 3113130073. The reversal of 3113130055 is 5500313113.

3113130055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3113130055 - 23 = 3113130047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44473252 + ... + 44473321.

It is an arithmetic number, because the mean of its divisors is an integer number (533679444).

Almost surely, 23113130055 is an apocalyptic number.

3113130055 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

3113130055 is a deficient number, since it is larger than the sum of its proper divisors (1156305497).

3113130055 is an equidigital number, since it uses as much as digits as its factorization.

3113130055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88946585.

The product of its (nonzero) digits is 675, while the sum is 22.

The square root of 3113130055 is about 55795.4304132516. The cubic root of 3113130055 is about 1460.1554308471.

Adding to 3113130055 its reverse (5500313113), we get a palindrome (8613443168).

The spelling of 3113130055 in words is "three billion, one hundred thirteen million, one hundred thirty thousand, fifty-five".

Divisors: 1 5 7 35 88946573 444732865 622626011 3113130055