Base | Representation |
---|---|
bin | 1001000011111000011… |
… | …11111111011110000111 |
3 | 1002202120120200000001212 |
4 | 10201330033333132013 |
5 | 20100041441242411 |
6 | 355004111242035 |
7 | 31330566066422 |
oct | 4417417773607 |
9 | 1082516600055 |
10 | 311322212231 |
11 | 1100382aa998 |
12 | 5040521931b |
13 | 23485730384 |
14 | 110d4b289b9 |
15 | 817169868b |
hex | 487c3ff787 |
311322212231 has 2 divisors, whose sum is σ = 311322212232. Its totient is φ = 311322212230.
The previous prime is 311322212189. The next prime is 311322212233. The reversal of 311322212231 is 132212223113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311322212231 is a prime.
It is a super-2 number, since 2×3113222122312 (a number of 24 digits) contains 22 as substring.
Together with 311322212233, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 311322212197 and 311322212206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311322212233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155661106115 + 155661106116.
It is an arithmetic number, because the mean of its divisors is an integer number (155661106116).
Almost surely, 2311322212231 is an apocalyptic number.
311322212231 is a deficient number, since it is larger than the sum of its proper divisors (1).
311322212231 is an equidigital number, since it uses as much as digits as its factorization.
311322212231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864, while the sum is 23.
Adding to 311322212231 its reverse (132212223113), we get a palindrome (443534435344).
The spelling of 311322212231 in words is "three hundred eleven billion, three hundred twenty-two million, two hundred twelve thousand, two hundred thirty-one".
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