Base | Representation |
---|---|
bin | 101101010011011111001… |
… | …010001001000011110111 |
3 | 102000121222020202212100101 |
4 | 231103133022021003313 |
5 | 402002014334100043 |
6 | 10342121434054531 |
7 | 440633324626354 |
oct | 55233712110367 |
9 | 12017866685311 |
10 | 3113300300023 |
11 | aa0385946071 |
12 | 423465b7a447 |
13 | 1977769b5854 |
14 | aa98253362b |
15 | 55eb644d24d |
hex | 2d4df2890f7 |
3113300300023 has 2 divisors, whose sum is σ = 3113300300024. Its totient is φ = 3113300300022.
The previous prime is 3113300300021. The next prime is 3113300300029. The reversal of 3113300300023 is 3200030033113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3113300300023 - 21 = 3113300300021 is a prime.
Together with 3113300300021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113300300021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556650150011 + 1556650150012.
It is an arithmetic number, because the mean of its divisors is an integer number (1556650150012).
Almost surely, 23113300300023 is an apocalyptic number.
3113300300023 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113300300023 is an equidigital number, since it uses as much as digits as its factorization.
3113300300023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 19.
Adding to 3113300300023 its reverse (3200030033113), we get a palindrome (6313330333136).
The spelling of 3113300300023 in words is "three trillion, one hundred thirteen billion, three hundred million, three hundred thousand, twenty-three".
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